Cambridge A Level Mathematics 9709 · Pure 1

Integration

Integration is differentiation run backwards: given a gradient function, it recovers the original curve; given a curve, it measures the area underneath it. In Cambridge 9709 Pure 1 it is the final topic of the syllabus and one of the heaviest-weighted — and the examiner reports are blunt about where its marks go missing: sign errors and incomplete working, not conceptual failure.

Updated 20 August 2026

How much it is worth

Integration: 381 marks across 42 real Cambridge 9709 papers — 12.1% of the total, and it came up on every one of them. How that ranks against every other 9709 topic →

The reverse power rule

Raise the power by one, divide by the new power, add a constant:

∫axn dx=axn+1n+1+c(n≠−1)

As with differentiation, rewrite roots and fractions as powers before you start: x=x1/2, 3x2=3x−2. The negative-power cases are where signs go wrong: ∫3x−2dx=−3x−1+c — raising −2 by one gives −1, and dividing by −1 flips the sign.

Integrating (ax + b)ⁿ

The chain rule in reverse: raise the power, divide by the new power, and divide by the bracket’s coefficient:

∫(ax+b)n dx=(ax+b)n+1a(n+1)+c

Example: ∫(3x−2)5 dx=(3x−2)618+c. The divide-by-a is the single most forgotten step in P1 integration — checking by differentiating your answer takes five seconds and catches it every time.

Finding the constant of integration

When a question gives dydx and a point on the curve, the constant is recoverable — and required:

  1. Integrate, writing + c.
  2. Substitute the given point into your expression.
  3. Solve for c and state the full equation of the curve.

“Find the equation of the curve” questions are marked on exactly this chain; an answer with no c (or with c never evaluated) caps the marks immediately.

Definite integrals

A definite integral has limits and produces a number — substitute the top limit, substitute the bottom limit, subtract:

∫13(2x+1) dx=[x2+x]13=(9+3)−(1+1)=10

Write the square-bracket stage explicitly — it carries the method mark — and keep the subtraction in brackets: most sign errors on definite integrals happen when the lower limit’s value is negative and the brackets were skipped.

Areas under and between curves

The area between a curve and the x-axis from a to b is ∫aby dx. Two refinements matter in P1:

  • Region below the axis: the integral comes out negative; the area is its magnitude. If the region crosses the axis, split at the root and add the pieces’ absolute values.
  • Between two curves: ∫ab(ytop−ybottom) dx, with a and b the intersection points — found by solving the curves equal, with working shown.

Worked example

Worked example

The curve y = 6x − x² and the line y = 2x intersect at the origin and at another point. Find the area enclosed between them.

Step 1 — intersections. 6x−x2=2x⇒4x−x2=0⇒x(4−x)=0, so x=0 and x=4.

Step 2 — top minus bottom, integrated between the intersections. On 0<x<4 the curve sits above the line:

∫04(6x−x2−2x)dx=∫04(4x−x2)dx=[2x2−x33]04

Step 3 — evaluate. (32−643)−0=323 square units. Leave it exact — 323, not 10.67 — unless the question says otherwise.

The mistakes that lose the marks

  1. 1.Sign errors on negative powers

    ∫x−3dx=x−2−2+c=−12x2+c. Raise the power towards zero and let the division carry the sign — then differentiate back to check.

  2. 2.Forgetting to divide by the bracket's coefficient

    ∫(3x−2)5dx needs division by both 6 and 3. If the inside of the bracket has a coefficient other than 1, your answer owes a division by it.

  3. 3.Dropping + c in indefinite integrals

    Every indefinite integral ends + c — and in “find the equation of the curve” questions the whole point is evaluating it. Write it the moment you integrate.

  4. 4.Treating below-axis area as negative (or ignoring the crossing)

    Areas are positive. If the curve crosses the axis inside your limits, one integral straight across cancels area against itself — split at the root, take magnitudes, add.

  5. 5.Skipping the bracketed subtraction stage in definite integrals

    Write [F(x)]ab=F(b)−F(a) with both values in brackets before simplifying. The stage is a method mark, and the brackets are what stop −(−2) becoming −2.

Common questions

Why can't n = −1 in the reverse power rule?

Raising −1 by one gives zero, and dividing by zero is undefined. The integral of x−1 is ln⁡∣x∣ — which belongs to Pure 3, not Pure 1, so a P1 question will never need it.

When do you use integration instead of differentiation?

Differentiate when you’re asked about gradient, tangent, normal, stationary points or rates. Integrate when you’re given a gradient and asked for the curve, or asked for an area. Examiners note candidates doing the opposite operation under time pressure — the question’s nouns tell you which way to go.

Do you need volumes of revolution in Pure 1?

Yes. Rotating a region about the x-axis gives volume V=π∫aby2 dx (about the y-axis, π∫x2 dy). Square the whole expression for y before integrating — expanding that square is usually where the marks sit.

Integration on real papers

The papers that leaned on it hardest, as a share of the paper. Each one has its own page on Quanta with the full topic breakdown:

Every 9709 past-paper question on integration

80 questions across 42 papers, 381 marks in all, newest first. Open a paper to sit it on Quanta and have these questions marked.

PaperQuestion (marks)
9709/11/O/N/25Q8 (7), Q11 (5)
9709/12/O/N/25Q4 (5), Q5 (5)
9709/13/O/N/25Q9 (8)
9709/11/M/J/25Q2 (4), Q4 (5)
9709/12/M/J/25Q6 (6), Q9 (6)
9709/13/M/J/25Q3 (4), Q7 (4)
9709/12/F/M/25Q9 (7), Q10 (9)
9709/11/O/N/24Q5 (4), Q7 (4)
9709/12/O/N/24Q7 (5), Q10 (4)
9709/13/O/N/24Q9 (4)
9709/11/M/J/24Q9 (6)
9709/12/M/J/24Q6 (5), Q9 (4)
9709/13/M/J/24Q6 (4), Q9 (3)
9709/12/F/M/24Q1 (3), Q3 (5), Q11 (7)
9709/11/O/N/23Q8 (5), Q10 (6)
9709/12/O/N/23Q3 (4), Q9 (5)
9709/13/O/N/23Q1 (4), Q11 (6)
9709/11/M/J/23Q10 (5), Q11 (3)
9709/12/M/J/23Q1 (3), Q5 (4)
9709/13/M/J/23Q9 (4), Q10 (5)
9709/12/F/M/23Q10 (4), Q11 (9)
9709/11/O/N/22Q2 (4), Q10 (5)
9709/12/O/N/22Q8 (4), Q11 (5)
9709/13/O/N/22Q7 (3), Q10 (4)
9709/11/M/J/22Q7 (5), Q10 (5)
9709/12/M/J/22Q3 (4), Q6 (5)
9709/13/M/J/22Q8 (4), Q10 (4)
9709/12/F/M/22Q1 (4), Q8 (5)
9709/11/O/N/21Q9 (4), Q10 (8)
9709/12/O/N/21Q4 (4), Q11 (6)
9709/13/O/N/21Q8 (6), Q10 (4)
9709/11/M/J/21Q1 (4), Q11 (4)
9709/12/M/J/21Q9 (6), Q11 (4)
9709/13/M/J/21Q1 (3), Q11 (3)
9709/12/F/M/21Q6 (4), Q11 (4)
9709/11/O/N/20Q2 (4), Q12 (6)
9709/12/O/N/20Q7 (4), Q10 (2)
9709/13/O/N/20Q2 (5), Q10 (5)
9709/11/M/J/20Q11 (6)
9709/12/M/J/20Q8 (5)
9709/13/M/J/20Q2 (4), Q11 (7)
9709/12/F/M/20Q3 (4), Q10 (4)

Practise integration against real mark schemes

Quanta has real Cambridge A Level Maths 9709 past-paper questions, broken into skill checkpoints, marked criterion by criterion the way examiners mark — and it tracks which skills you’re missing. Free for individual students.

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