Cambridge A Level Mathematics 9709 · Pure 1

Binomial expansion

The binomial expansion writes out powers of a two-term bracket without multiplying it repeatedly. For a positive integer nn — the Pure 1 case —

(a+b)n=r=0n(nr)anrbr(a+b)^n = \sum_{r=0}^{n} \binom{n}{r} a^{n-r} b^{r}

Most P1 binomial questions don’t want the whole expansion: they want one specific term or coefficient, and Cambridge’s examiner reports repeatedly note candidates expanding everything (wasting time) or forgetting to raise the bb-part’s coefficient to its power (losing the marks).

Updated 20 August 2026

The coefficients: nCr

The numbers (nr)\binom{n}{r} (said “n choose r”, calculator key nCr) are the rows of Pascal’s triangle:

(nr)=n!r!(nr)!,(62)=15\binom{n}{r} = \frac{n!}{r!\,(n-r)!}, \qquad \binom{6}{2} = 15

For small nn, Pascal’s triangle by hand is fine; for (2x2)10(2-\tfrac{x}{2})^{10}-style questions, nCr is faster and less error-prone. Symmetry helps too: (nr)=(nnr)\binom{n}{r} = \binom{n}{n-r}.

The general term — the tool that answers everything

The term containing brb^r in (a+b)n(a+b)^n is

Tr+1=(nr)anrbrT_{r+1} = \binom{n}{r} a^{n-r} b^{r}

Every “find the coefficient of xkx^k” question is this formula plus one line of index work: set the power of xx inside brb^r equal to kk, solve for rr, substitute. The critical discipline: aa and bb are the whole terms, coefficients and signs included. In (23x)5(2-3x)^5, a=2a = 2 and b=3xb = -3x — so brb^r carries (3)r(-3)^r, not just xrx^r.

Worked example

Worked example

Find the coefficient of x³ in the expansion of (2 − 3x)⁵.

Step 1 — set up the general term with a=2a = 2, b=3xb = -3x, n=5n = 5:

Tr+1=(5r)25r(3x)rT_{r+1} = \binom{5}{r}\, 2^{5-r} (-3x)^r

Step 2 — pick out x³: need r=3r = 3.

(53)22(3)3x3=10×4×(27)x3=1080x3\binom{5}{3}\, 2^{2} (-3)^3 x^3 = 10 \times 4 \times (-27)\, x^3 = -1080x^3

Answer: the coefficient is 1080-1080. Note all three factors were needed — the nCr, the power of 2, and the cube of 3-3 with its sign. Each is typically worth working credit; omitting (3)3(-3)^3 and writing 3-3 is the classic slip.

Finding unknowns from a given coefficient

The harder P1 variant runs the machine backwards: “the coefficient of x2x^2 in (1+ax)6(1+ax)^6 is 60; find aa.” Same general term:

(62)a2=15a2=60    a2=4    a=±2\binom{6}{2} a^2 = 15a^2 = 60 \;\Rightarrow\; a^2 = 4 \;\Rightarrow\; a = \pm 2

Keep both roots unless the question restricts aa (“where a>0a > 0”). Examiner reports specifically call out dropped negative roots here. A second common variant multiplies two expansions — e.g. (1+2x)(1x)7(1+2x)(1-x)^7 — where the target power collects from two products: constant × xkx^k term plus xx term × xk1x^{k-1} term.

The mistakes that lose the marks

  1. 1.Forgetting to raise b's coefficient to the power

    In (23x)5(2-3x)^5, the x3x^3 term carries (3)3=27(-3)^3 = -27, never 3-3. Bracket the whole term — (3x)r(-3x)^r — before separating number from letter.

  2. 2.Losing the sign in (a − b)ⁿ

    Treat the minus as part of bb: b=3xb = -3x. Odd powers of bb are negative, even powers positive — if your expansion doesn’t alternate, something’s wrong.

  3. 3.Expanding the whole bracket when one term was asked

    “Find the coefficient of x3x^3” needs the general term and one value of rr — three lines. A full ten-term expansion invites arithmetic slips and burns minutes the paper doesn’t give back.

  4. 4.Confusing 'coefficient' with 'term'

    The term is 1080x3-1080x^3; the coefficient is 1080-1080. Answer the noun the question used.

  5. 5.Dropping the ± when solving for an unknown

    a2=4a^2 = 4 has two solutions. Write a=±2a = \pm 2, then discard one only if the question gives a reason to.

Common questions

Is the binomial expansion for negative or fractional powers in Pure 1?

No — P1 covers positive integer nn only, where the expansion is exact and finite. The infinite series for negative and fractional powers (with its validity condition x<1|x| < 1) belongs to Pure 3.

Do I have to simplify every coefficient?

Yes — mark schemes state coefficients as evaluated numbers (1080-1080, not 10×4×(27)10 \times 4 \times (-27)). Leave the arithmetic line visible, then finish it.

How is the binomial expansion examined in 9709 P1?

Usually one 4–6 mark question: a specific coefficient, an unknown constant from a given coefficient, or a two-bracket product where the target power collects from two places. It also feeds series questions — the first terms of an expansion reappearing as a geometric or arithmetic progression.

Practise binomial expansion against real mark schemes

Quanta has real Cambridge A Level Maths 9709 past-paper questions, broken into skill checkpoints, marked criterion by criterion the way examiners mark — and it tracks which skills you’re missing. Free for individual students.

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